Import a Controller in CakePHP
If you want to access some predefined controller in another controller in CakePHP. You can do this as explained in following example.
<?php
App::import('Controller', 'Events');
class HomesController extends AppController {
var $name = 'Homes';
var $Events;
function beforeFilter() {
$this->Events =& new EventsController();
$this->Events->constructClasses();
}
function index() {
$this->Events->index();
}
}
?>
Model without Table in CakePHP
This is explained in following example
<?php
class ModelWithoutTable extends AppModel {
var $useTable = false;
}
?>
Controller without Model in CakePHP
In some cases you may need to have a controller without its own model. This might be because you are using other models. You can do this by using an empty array.
<?php
class HomesController extends AppController {
var $name = 'Homes';
var $uses = array(); // Don't use Home Model
function index() {
}
}
?>
How to add Google Analytics to Question2Answer plateform
Go to your Google Analytics account and get code for you forum which you need to track.
Now login to your Question2Answer forum from your admin account and follow these steps
1. Go to admin section
2. Click on ‘layout’ tab.
3. Check option “Custom HTML in
4. Upon checking option, you’ll get textbox.
5. Enter the tracking code you got from Google Analytics account.
Starting tomcat in debug mode – Linux
To start tomcat in debug mode, you need to set JPDA_TRANSPORT=dt_socket and JPDA_ADDRESS=9000 environment variable. To set these variable for a session only, open command prompt and run following commands
export CATALINA_HOME=/home/xyz/opt/tomcat export JPDA_TRANSPORT=dt_socket export JPDA_ADDRESS=9000
now start tomcat using following command
$ %CATALINA_HOME%/bin/catalina.sh jpda start
Setting this variable in your personal ~/.bashrc file has the advantage that it will always be set (for you, as a user) each time you log in or reboot the system. To do so, open ~/.bashrc in a text editor (or create the file if it doesn’t already exist) and insert the following line anywhere in the file
export CATALINA_HOME=/home/xyz/opt/tomcat export JPDA_TRANSPORT=dt_socket export JPDA_ADDRESS=9000
Save and close .bashrc.
You must logout and login again to make your change take effect. or source your .bashrc file to make your change take effect for the current session
$ source ~/.bashrc
Changing project type form general to java in eclipse
You have a project, which is basically a java project but during checking out the project or creating a new project, you didn’t selected type of project as java. You are stuck now as there is no option to change it to java type in eclipse UI.
You can change type of project by modifying.projectfile, located in the root directory of your project. Open .project file in any text editor and search for text “natures”. You’ll see an empty natures node.
<natures> </natures>
Change this value to
<natures>
<nature>org.eclipse.jdt.core.javanature</nature>
</natures>
See Servlet Spec 2.3, section 9.7.2
If you are getting warnings or errors related with Servlet Specification, version 2.3, section 9.7.2. It means that you are trying to override web container’s implementation classes from your applications classes.
Servlet specification 2.3 section 9.7.2 says this clearly
The classloader that a container uses to load a servlet in a WAR must allow the developer to load any resources contained in library JARs within the WAR following normal J2SE semantics using getResource. It must not allow theWAR to override J2SE or Java servlet API classes. It is further recommended that the loader not allow servlets in theWAR access to the web container’s implementation classes. It is recommended also that the application class loader be implemented so that classes and resources packaged within the WAR are loaded in preference to classes and resources residing in container-wide library JARs.
You can get away from these warnings by doing one of the following
1. server-api.jar is needed to compile an application and is not required in application war to run application as container already have this file. You must remove this file from WEB-INF/lib.
2. It can be because of other jar files that are bundled with container. e.g. j2ee.jar. You need to remove this file from your application’s lib directory.
In tomcat 6, $CATALINA_HOME/lib/ contains all the jar file which one should not override with those of application’s jar. tomcat 5 has these jars in $CATALINA_HOME/common/lib folder.
Running a process in background/foreground in linux
Run process in background
To run a command in background, you can use following command at command prompt
Above command will make your process run in background. You need to make sure that process is finished before logging off. A process run by above command will be terminated as soon as you logout.
If you want to run a command in background even after you logout then you can use following command
nohup Run a command immune to hang ups, with output to a non-tty.
This command will run your process in background even if you logs out.
Making current process to run in background
You can make current process as a background process by issuing following commands.
$ bg
You need to remember that the process is running in background, if you logs out then process will be terminated. You can disown to avoid killing the process after you close the terminal.
$ bg
$ disown
Execute following command to run any process in background
You can find process id by issues ps command. It displays the list of currently running process and their process ids. Use ps aux to see all the process currently running on your system including from other users. Use top to get updated list of all the processes running currently.
Run a process in foreground
java.util.regex.PatternSyntaxException: Unclosed character class
Exception in thread "main" java.util.regex.PatternSyntaxException: Unclosed character class near index 1 $[ ^ at java.util.regex.Pattern.error (Pattern.java:1503) at java.util.regex.Pattern.clazz(Pattern.java:2016) at java.util.regex.Pattern.sequence(Pattern.java:1560) at java.util.regex.Pattern.expr(Pattern.java:1520) at java.util.regex.Pattern.compile (Pattern.java:1288) at java.util.regex.Pattern.<init>(Pattern.java:1044) encountered while splitting the string using a delimiter which contains "["
JSON communication between server and client Part1
JSON (JavaScript Object Notation) provides lightweight data exchange between server and client. It is human readable.
Sending data in JSON format from server to client:
There are APIs present for many languages (Java, ASP, Flex, C, C++ etc). With the help of these APIs, we can get JSON representation for data or objects. This data can be send to client just like some other data.
On the client side browser can handle this format and one can retrieve the information send from server.
I am writing code sample for spring framework
public void getJSONInfo(HttpServletRequest request, HttpServletResponse response) throws Exception {
JSONObject result = new JSONObject();
try {
Object obj = new Object();
// To get JSON data from obj
JSONObject jsonObj = JSONObject.fromObject(obj);
result.put("result", "success");
result.put("jsonInfo", jsonObj);
} catch (Exception e) {
result.put("result", "error");
} finally {
// Write this jsonObj in HttpServletResponse
response.getWriter().print(result);
response.flushBuffer();
}
}
While on the client side, I am using jquery to make AJAX request,
function getJSONInfo() {
$.ajax({
url: '../location?q=getJSONInfo',
type: "POST",
cache: false,
dataType: "json",
success: function(response){
alert(response.jsonInfo);
},
error: function(msg){
}
});
}
As we can see from the example, an ajax request is made to get JSONInfo and result is displayed in popup window.
Sending data in JSON format from client to server will be covered in part2